(1/6)^3x-1=36^x-7

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Solution for (1/6)^3x-1=36^x-7 equation: 



(1/6)^3x-1=36^x-7

We move all terms to the left:

(1/6)^3x-1-(36^x-7)=0



Domain of the equation: 6)^3x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/6)^3x-(36^x-7)-1=0

We get rid of parentheses

(+1/6)^3x-36^x+7-1=0

We multiply all the terms by the denominator


(+1-36^x*6)^3x+7*6)^3x-1*6)^3x=0

Wy multiply elements

252x^2+(+1-36^x*6)^3x=0

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